Answer:
The answer to your question is 97 ml
Explanation:
Data
volume = ? ml
concentration = 1.01 M LiNO₃
mass = 6.63 g
Process
1.- Calculate the molecular weight of LiNO₃
LiNO₃ = (1 x 6.94) + (1 x 14) + (16 x 3)
= 6.94 + 14 + 48
= 69 g
2.- Calculate the moles of LiNO₃
69 g ------------------ 1 mol
6.63 g --------------- x
x = (6.63 x 1) / 69
x = 0.096 moles
3.- Calculate the volume
Molarity = moles / volume
-Solve for volume
Volume = Molarity x moles
-Substitution
Volume = 1.01 x 0.096
-Result
Volume = 0.097 l or 97 ml
The number of mL of of 1.01 M LiNO3 solution when solution has 6.63 g of solute should be 97 ml.
Since
concentration = 1.01 M LiNO₃
mass = 6.63 g
First we have to determine the molecular weight of LiNO₃ i.e.
LiNO₃ = (1 x 6.94) + (1 x 14) + (16 x 3)
= 6.94 + 14 + 48
= 69 g
Now the moles of LiNO₃
69 g ------------------ 1 mol
6.63 g --------------- x
x = (6.63 x 1) / 69
x = 0.096 moles
Now the volume is
Molarity = moles / volume
It can be like
Volume = Molarity x moles
= 1.01 x 0.096
= 0.097 l or 97 ml
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