Answer:
970.2 N
Explanation:
We are given that
Length of ladder=2.7 m
Mass,M=11 kg
Coefficient of friction=[tex]\mu=0.45[/tex]
[tex]\theta=51^{\circ}[/tex]
Mass of painter=8M
Distance from base=d
We have to find the magnitude of the normal force exerted by the floor on the ladder.
Normal force exerted by floor on the ladder=[tex]mg+8mg=9mg[/tex]
Where [tex]g=9.8m/s^2[/tex]
Normal force exerted by floor on the ladder=[tex]9\times 11\times 9.8=970.2N[/tex]