Answer:
[tex]4.6\times 10^{-3} m[/tex]
Explanation:
We are given that
Length of slab=L=11 m
[tex]T_1=15^{\circ}[/tex]
[tex]T_2=50^{\circ}[/tex]
We have to find the width of expansion.
We know that by linear expansion
[tex]\Delta L=L\alpha (T_2-T_1)[/tex]
Where [tex]\alpha=12\times 10^{-6}/^{\circ} C[/tex]
Substitute the values
[tex]\Delta L=11\times 12\times 10^{-6}\times (50-15)=4.62\times 10^{-3} m[/tex]
[tex]\Delta L=4.6\times 10^{-3} m[/tex]
