Complete Question
The diagram for this question is shown on the first uploaded image
Answer:
The current is [tex]I= 120 A[/tex]
the direction is counter clockwise
Explanation:
From the question we are told that
The speed of the bar is [tex]v = 30.0m/s[/tex]
The magnetic field is [tex]B = 8.0 T[/tex]
The resistace is [tex]R = 6.0\ \Omega[/tex]
The seperation is [tex]L = 3.0m[/tex]
The induced emf due to the change in magnetic flux as a result of the bar
sliding is mathematically represented as
[tex]\epsilon = -B lv[/tex]
Substituting values
[tex]\epsilon =- 8.0 * 30 * 3[/tex]
[tex]= - 720V[/tex]
According to ohm law
[tex]I = \frac{|\epsilon|}{R}[/tex]
Substituting values
[tex]I = \frac{|-720|}{6}[/tex]
[tex]I= 120 A[/tex]
According to Lenz's law the emf should be opposing the magnetic force which produced it so since the magnetic force is moving in the clockwise direction the current due to the emf would be moving in a counter clockwise direction
