Area of sector JKL will be 47.89 square units
Given in the question,
- [tex]m\angle JKL=112^0[/tex]
- Measure of radius JK = 7 units
Expression to be used to measure the area of the sector JKL,
Area = [tex]\frac{\theta}{360^0}(\pi r^2)[/tex]
Here, [tex]\theta=[/tex] Angle formed at the center by the arc
[tex]r=[/tex] radii
Area of the sector JKL = [tex]\frac{112}{360^0}(\pi )(7)^2)[/tex]
= 47.892
≈ 47.89 square units
Therefore, area of the sector JKL will be 47.89 square units
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