Let's say that the number density of galaxies in the universe is, on average, 3 × 10–68 galaxies/m3. If astronomers could observe all galaxies out to a distance of 1010 light-years, how many galaxies would they find? (Note that there are 1016 meters in 1 light-year.)

Respuesta :

Answer:

They would find [tex]3.14\times 10^{10}[/tex]galaxies.

Explanation:

Given that,

The number of density of galaxies in the universe is 3×10⁻⁶⁸ galaxies /m³.

Assuming that, the astronomers are observing at the center of sphere.

So, they can observe the sphere of space whose radius 10¹⁰ light years.

1 light year = 10¹⁶ meters

10¹⁰ light years =10¹⁰ .10¹⁶ meters

                         =10²⁶meters

The volume of the space is

=[tex]\frac43 \pi r^3[/tex]

[tex]=\frac43 \pi (10^{26})^3[/tex] m³

[tex]=\frac43 \pi 10^{78}[/tex] m³.

The number of galaxies

= Volume of the space × density

[tex]=(3\times 10^{-68}\ galaxies /m^3)\times(\frac43 \pi . 10^{78}\ m^3)[/tex]

[tex]=10^{10}\pi[/tex] galaxies

= [tex]3.14\times 10^{10}[/tex]galaxies

They would find [tex]3.14\times 10^{10}[/tex]galaxies.