Answer:
So we got:
[tex]\left(m^{\frac{2}{3}}n^{\frac{-1}{3}}\right)^6[/tex]
[tex]m^4\left(n^{\frac{-1}{3}}\right)^6\\[/tex]
More attention for [tex](n^{\frac{-1}{3}}\right))^6\\[/tex]
[tex]n^{-2}[/tex]
[tex]\frac{1}{n^2}[/tex]
Join:
[tex]m^4\frac{1}{n^2}[/tex]
[tex]\frac{1\cdot \:m^4}{n^2}\\\frac{m^4}{n^2}[/tex]
Therefore, the answer is [tex]\frac{m^4}{n^2}[/tex] , letter A
