Answer:
[tex]\large \boxed{\text{3.3 mol}}[/tex]
Explanation:
Mg + 2HCl ⟶ MgCl₂ + H₂
n/mol: 6.6
The molar ratio is 1 mol MgCl₂:2 mol HCl.
[tex]\text{Moles of MgCl}_{2} = \text{6.6 mol HCl} \times \dfrac{\text{1 mol MgCl}_{2}}{\text{2 mol HCl}}= \textbf{3.3 mol MgCl}_{2}\\\\\text{The reaction produces $\large \boxed{\textbf{3.3 mol MgCl}_{2}}$}[/tex]
