Given:
In the given diagram
Each small box along X axis = 2 unit
Each small Box along Y axis = 2 unit
For rectangle:
Length = 16 unit
Width = 16 unit
For triangle 1
Base = 8 unit
Height = 6 unit
For triangle 2
Base = 8 unit
Height = 4 unit
For triangle 3
Base = 16 unit
Height = 12 unit
Formula
Area of the trapezoid is
[tex]A = R -T_{1} -T_{2} -T_{3}[/tex]
Where, [tex]A[/tex] be the area of the trapezoid
[tex]R[/tex] be the area of the rectangle
[tex]T_{1} ,T_{2} ,T_{3}[/tex] be the area of the triangle 1, 2 and 3 respectively.
[tex]R = lb[/tex] where, l be length and b the width
[tex]T_{1} = \frac{1}{2} bh[/tex], where, b be the base and h be the height
Now,
Taking, l = 16 and b = 16 we get,
[tex]R = (16)(16)[/tex] = 256 sq unit
For Triangle 1
Taking, b = 8 and h = 6 we get,
[tex]T_{1} = \frac{1}{2}(8)(6)[/tex] sq unit
[tex]T_{1} = 24[/tex] sq unit
For Triangle 2
Taking, b = 8 and h = 4 we get,
[tex]T_{2} = \frac{1}{2}(8)(4)[/tex] sq unit
[tex]T_{2} = 16[/tex] sq unit
For Triangle 3
Taking, b = 16 and h = 12 we get,
[tex]T_{3} = \frac{1}{2}(16)(12)[/tex] sq unit
[tex]T_{3} = 96[/tex] sq unit
Therefore,
The area of the trapezoid is = 256-24-16-96 sq unit = 120 sq unit
Hence,
Area of rectangle =256 square units
Area of triangle 1 = 24 square units
Area of triangle 2 = 16 square units
Area of triangle 3 = 96 square units
Area of trapezoid = 120 square units