muma15 muma15
  • 22-04-2020
  • Mathematics
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What is the value of n when (9)^2n-1 = (27)^n+2

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nktselepov
nktselepov nktselepov
  • 22-04-2020

[tex]9^{2n-1} = 27^{n+2} \\ ( {3}^{2} ) ^{2n - 1} = ( {3}^{3} )^{ n + 2} \\ {3}^{4n - 2} = {3}^{3n + 6} \\ 4n - 2 = 3n + 6 \\ 4n - 3n = 6 + 2 \\ n = 8[/tex]

Answer: n=8

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