A thin copper rod that is 1.0 m long and has a mass of 0.050 kg is in a magnetic field of 0.10 t. What minimum current in the rod is needed in order for the magnetic force to cancel the weight of the rod?

Respuesta :

Answer:

Current is 5Amperes

Explanation:

Given length L=1m,mass M=0.05kg, magnetic field B= 0.10T since it's minimum sin90°= 1

Note

ILBsin#=mg

We're Current I= mg/LBsin#

I=0.05*10/1*0.10=5Amperes