ZnCl2 is used in soldering flux, an alloy used to join two metals together. Determine the moles of Cl- ions in 2.50 mol ZnCl2.

5.00 mol Cl-

0.500 mol Cl-

1.75 mol Cl-

15.0 mol Cl-

Respuesta :

Answer : The number of moles of [tex]Cl^-[/tex] ions are, 5.00 mole.

Explanation :

When 1 mole of [tex]ZnCl_2[/tex] dissociates then it gives 1 mole of [tex]Zn^{2+}[/tex] ion and 2 moles of [tex]Cl^-[/tex] ions.

As we are given that there are 2.50 mole of [tex]ZnCl_2[/tex].

Now we have to determine the number of moles of [tex]Cl^-[/tex] ions.

As, 1 mole of [tex]ZnCl_2[/tex] dissociate to give 2 moles of [tex]Cl^-[/tex] ions.

So, 2.50 mole of [tex]ZnCl_2[/tex] dissociate to give [tex]2\times 2.50=5.00[/tex] moles of [tex]Cl^-[/tex] ions.

Therefore, the number of moles of [tex]Cl^-[/tex] ions are, 5.00 mole.

There are 5.00 moles of Cl- in 2.50 moles of ZnCl2.

We have that the amount of moles of ZnCl2 is equal to 2.50 moles, so, according to the equation that forms this compound we can say that:

                                      [tex]Zn + 2Cl[/tex] ⇒[tex]ZnCl_{2}[/tex]

So, 1 mole ZnCl2 of  decomposes as 1 Zn ion and 2 Cl ions, that is, the number of moles of chlotide is twice the number of moles of ZnCl2:

                                     [tex]2 \times 2.50 = 5.00 moles[/tex]

So, there are 5.00 moles of Cl- in 2.50 moles of ZnCl2.

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