Answer:
The electrostatic force between two charge doubles when when the amount of charge on one object doubles.
Explanation:
Force between two charge particle [tex]F=\frac{1}{4\pi\epsilon } \frac{q_1\cdot\ q_2}{r^{2} }[/tex]
Where, [tex]\frac{1}{4\pi\epsilon } = constant[/tex]
[tex]q_1,q_2\ magnitude\ of\ charges.\\r\ is\ the\ distance\ between\ the\ particles.[/tex]
Now suppose as per the question
[tex]q_1= 2 q_1\ with\ q_2\ and\ r\ with\ same\ value.\\Hence\ force\ between\ the\ particle\ F_2 =2 F[/tex]
Hence, electrostatic force between two charge doubles when when the amount of charge on one object doubles.
