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Suppose two dice (one red, one green) are rolled. Consider the following events. A: the red die shows 1; B: the numbers add to 6; C: at least one of the numbers is 3; and D: the numbers do not add to 11. Express the given event in symbolic form.
Either the numbers add to 11 or the red die shows a 1.
D ∩ B
D ∩ A
D' ∪ A
D' ∩ A
D' ∪ B

How many elements does it contain?

Respuesta :

Answer:

(a)(C)[tex]D^c \cup A[/tex]

(b)8 elements

Step-by-step explanation:

Ina toss of a red and green dice, given the events:

  • A: the red die shows 1;
  • B: the numbers add to 6;
  • C: at least one of the numbers is 3; and
  • D: the numbers do not add to 11.

[tex]D^c[/tex]=The numbers do add up to 11.

Therefore, the event: Either the numbers add to 11 or the red die shows a 1 is written as: [tex]D^c \cup A[/tex]

(b)

Sample Space of A={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)}

Sample Space of [tex]D^c[/tex]={(5,6),(6,5)}

[tex]D^c \cup A[/tex]={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(5,6),(6,5)}

[tex]D^c \cup A[/tex] contains 8 elements

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