Answer:
[tex]x=0[/tex] and [tex]2x+1=0[/tex]
Step-by-step explanation:
We are given that an equation
[tex]4x^2+2x[/tex]
We have to find the system of equation which can be used to find the roots of the given equation.
[tex]2x\times 2x+2x[/tex]
Taking 2 x common then we get
[tex]2x(2x+1)[/tex]
[tex]2x(2x+1)=0[/tex]
[tex]2x=0[/tex] and [tex]2x+1=0[/tex]
[tex]x=0[/tex] and [tex]2x+1=0[/tex]
[tex]2x=-1[/tex]
[tex]x=-\frac{1}{2}[/tex]
Hence, the system of equations which can be used to find the roots of the equation is given by
[tex]x=0[/tex] and [tex]2x+1=0[/tex]
