Respuesta :
Answer:I think it is C not positive though
Explanation:
In one of your trials you placed 5.5 grams of salt in 10 ml of water. (a) The w/w % is 35.48% (b) The w/v % is 55 % (c) The moles of NH₄Cl is 0.1 mol (d) The molarity of solution is 10 M.
How to calculate the percentage concentration (w/w) ?
Concentration % (w/w) = [tex]\frac{\text{Weight of solute}}{\text{Weight of solution}} \times 100[/tex]
Weight of solution = Solute + Solvent
= 5.5 g + 10g [ 1 ml water = 1 g water]
= 15.5
Concentration % (w/w) = [tex]\frac{\text{Weight of solute}}{\text{Weight of solution}} \times 100[/tex]
= [tex]\frac{5.5}{15.5} \times 100[/tex]
= 0.3548 × 100
= 35.48 %
How to calculate the percentage concentration (w/v) ?
Concentration %(w/v) = [tex]\frac{\text{Mass of solute (in g)}}{\text{Volume of solution (in ml)}} \times 100[/tex]
= [tex]\frac{5.5}{10} \times 100[/tex]
= 55%
How to find the number of mole ?
To calculate the number of moles of a substance we have to divide the given mass/weight of the substance by the molar mass of the substance.
Moles = [tex]\frac{\text{Given Mass}}{\text{Molar mass }}[/tex]
= [tex]\frac{5.5}{53.5}[/tex]
= 0.1 mol
What is Molarity ?
Molarity (M) is defined as the number of solute dissolved in per liter of solution.
Molarity (M) = [tex]\frac{\text{Number of moles of solute}}{\text{Volume of solution (in liters)}}[/tex]
Convert ml into l
1 ml = 0.001 liter
10 ml = 10 × 0.001
= 0.01 liter
Now put the value in above formula we get
Molarity (M) = [tex]\frac{\text{Number of moles of solute}}{\text{Volume of solution (in liters)}}[/tex]
= [tex]\frac{0.1}{0.01}[/tex]
= 10 M
Thus from the above conclusion we can say that In one of your trials you placed 5.5 grams of salt in 10 ml of water. (a) The w/w % is 35.48% (b) The w/v % is 55 % (c) The moles of NH₄Cl is 0.1 mol (d) The molarity of solution is 10 M.
Learn more about the Molarity here: https://brainly.com/question/26873446
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