Answer:
The answer is 74.5%.
Explanation:
As we know that % yield= [tex]\frac{actual yield}{theoretical yield}[/tex] x 100%.
Therefore,
Step 1 Calculate Theoretical yield:
0.112[tex]H_{2}[/tex] x [tex]\frac{1 mol H_{2} }{2.016 g of H{2} }[/tex] x [tex]\frac{4 mol H_{2}O }{4 mol H_{2} }[/tex] x [tex]\frac{18.02 g H_{2}O }{1 mol H_{2}O}[/tex] = 1.001 g [tex]H_{2}O[/tex]
Now Step 2
% yield = [tex]\frac{actual yield}{theoretical yield}[/tex] x 100% = [tex]\frac{0.745g}{1.001g}[/tex] = 74.5%
