An elevator cable lift a 755-kg elevator 5.8 M. what is the power expended if the elevator takes 6.2 seconds for the trip

The power expended if the elevator takes 6.2 seconds for the trip is 7,062.90Watt
Power is the rate of change of work done. Mathematically;
Power = force*distance/time
Given the following parameters:
Mass = 755kg
Substitute into the formula to have:
Power = 7550*5.8/6.2
Power = 7,062.90Watt
Hence the power expended if the elevator takes 6.2 seconds for the trip is 7,062.90Watt
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