The amount of copper that can be generated using 100g of Magnesium and 200g of [tex]CuCl_{2}[/tex] would be:
90g
Limiting reactant is [tex]CuCl_{2}[/tex]
Equation
[tex]Mg + CuCl2[/tex] → [tex]MgCl2 + Cu[/tex]
No. of moles in 100g of [tex]Mg[/tex] [tex]= 4.11 moles[/tex]
No. of moles in 200g of [tex]CuCI2[/tex] [tex]= 1.49 moles[/tex]
∵ Limiting reactant is [tex]CuCl_{2}[/tex]
We know,
[tex]1.49 moles[/tex] of [tex]CuCl_{2}[/tex] gives [tex]1.49 moles[/tex] of [tex]Cu[/tex]
and,
[tex]1.49 moles[/tex] of [tex]Cu[/tex] equals [tex]94.7 g[/tex] of [tex]Cu[/tex]
Hence,
The amount of copper that can be generated using 100g of Magnesium and 200g of [tex]CuCl_{2}[/tex] would be 90g.
Thus, 90g is the correct answer.
Learn more about "Reactant" here:
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