Answer:
[tex]2CO_{2}(g)+5H_{2}(g)\rightarrow C_{2}H_{2}(g)+4H_{2}O(g)-46.6kJ[/tex]
Explanation:
As energy is absorbed therefore it is an endothermic reaction. Hence energy value should be written in the product side with a negative sign.
Reaction: [tex]CO_{2}(g)+H_{2}(g)\rightarrow C_{2}H_{2}(g)+H_{2}O(g)[/tex]
C balance: [tex]2CO_{2}(g)+H_{2}(g)\rightarrow C_{2}H_{2}(g)+H_{2}O(g)[/tex]
H and O balance: [tex]2CO_{2}(g)+5H_{2}(g)\rightarrow C_{2}H_{2}(g)+4H_{2}O(g)[/tex]
Here 2 moles of [tex]CO_{2}[/tex] react. So, energy absorbed during the reaction is [tex](2\times 23.3)[/tex] kJ or 46.6 kJ
Energy balance: [tex]2CO_{2}(g)+5H_{2}(g)\rightarrow C_{2}H_{2}(g)+4H_{2}O(g)-46.6kJ[/tex]
Balanced thermochemical equation:
[tex]2CO_{2}(g)+5H_{2}(g)\rightarrow C_{2}H_{2}(g)+4H_{2}O(g)-46.6kJ[/tex]