Answer:
Explanation:
width of central diffraction maxima = 2 λD / d₁
λ is wave length of light , D is screen distance and d₁ is slit width
width of each interference fringe = λD / d₂ , d₂ is slit separation.
No of interference fringe in central diffraction fringe
= width of central diffraction maxima / width of each interference fringe
= 2 λD / d₁ x λDd₂ / λD
No = 2 d₂ / d₁
No = 5
5 = 2 d₂ / d₁
Since this number does not depend upon wavelength so it will remain the same
No of required fringe will be 5 .
right option
e ) 5.
When 900-nm light is incident on the same slit system the number is 5.
The given parameters:
The number of interference fringe in central diffraction fringe is calculated as follows;
[tex]n = \frac{width \ of \ central \ diffraction\ maxima}{ width \ of \ each \ interference\ fringe}\\\\n = \frac{2\pi \lambda D/d_1}{2\pi \lambda D/d_2} \\\\n = \frac{2d_2}{d_1}[/tex]
The number of number of interference fringe is independent of the wavelength.
Thus, when 900-nm light is incident on the same slit system the number is 5.
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