Answer : The change in boiling point is, [tex]0.94^oC[/tex]
Explanation :
Formula used :
[tex]\Delta T_b=i\times K_f\times m[/tex]
where,
[tex]\Delta T_b[/tex] = change in boiling point = ?
i = Van't Hoff factor = 3 (for MgI₂ electrolyte)
[tex]K_f[/tex] = boiling point constant for water = [tex]0.51^oC/m[/tex]
m = molality = 0.615 m
Now put all the given values in this formula, we get
[tex]\Delta T_b=3\times (0.51^oC/m)\times 0.615m[/tex]
[tex]\Delta T_b=0.94^oC[/tex]
Therefore, the change in boiling point is, [tex]0.94^oC[/tex]
