Answer:
32901 gallons
Step-by-step explanation:
First, we find the volume of the cylindrical water tank when it is full.
The volume of a cylinder is given as:
V = [tex]\pi r^2h[/tex]
where r = radius and h = height of the cylinder
The diameter of the tank is 20 feet, hence, its radius is 10 feet.
Volume, V, is therefore:
V = [tex]\pi * 10^2*20 = 6283.19 ft^3[/tex]
This is the volume of the tank, when it is full.
When it is 70% full, the volume will be:
[tex]\frac{70}{100} * 6283.19 = 4398.23 ft^3[/tex]
1 cubic foot ([tex]ft^3[/tex]) is 7.48 gallons.
Therefore, the volume of the 70% full tank in gallons will be:
4398.23 * 7.48 = 32901.05 gallons ≅ 32901 gallons
The tank contains 32901 gallons of water.
Answer:
32886.476 gal
Step-by-step explanation:
Given:
Diameter of tank 'd'= 20 ft
∴radius 'r'= d/2=> 20/2=> 10ft
Height 'h' = 20 ft
Volume of cylinder can be determined by
V= π r² h
Substituting the values in above equation
V= π (10)² (20) =>π(100)(20)
V=2000π ft³
When the tank is 70% full.
70% of 2000π =>0.7 x 2000π
1400π ft³
As we know that, 1ft³ = 7.481 gal
1400π ft³= 1400π x 7.481 gal
1400π ft³= 32886.476 gal
Therefore, if the tank is 70% full then 32886.476 gallons of water are in the tank
