The work needed in KJ/mol for a steady-state flow reversible adiabatic compression is : 2.229KJ
Given data :
Initial pressure ( P1 ) = 0.75 MPa
Final pressure ( P2 ) = 2 MPa
Temperature = 325 K
For FREON-12 refrigerant n = 1.4
Determine the work done in KJ/mol
Applying Peng-Robinson equation of state
[tex]W = \frac{RT}{n-1} [(\frac{p2}{p1})^{(\frac{n-1}{n} )} -1 ][/tex]
W = ( 8.314 * 325 ) / 0.4 * [ ( 2/0.75 )^0.29 - 1 ]
= 6755.125 * 0.33
= 2229.19 J ≈ 2.229 KJ
Hence we can conclude that The work needed in KJ/mol for a steady-state flow reversible adiabatic compression is : 2.229KJ
Learn more about Peng-Robinson equation of state : https://brainly.com/question/16177987
