Two right triangles, ABD and ACD, were created from ABC by

constructing AD 1 CB.

Follow these steps to prove that sin(B) = sin(C)

1. For

ABD, sin(B) = 1

Respuesta :

Answer:

Since their corresponding angles are congruent and the corresponding sides are in proportion

Step-by-step explanation:

For ABD,

Sin (B) = (AD ÷ AB) =1

∴ AD = AB

and if AD = AB

⇒ AD = AC   (since AD 1 CB).

From triangle ACD,

Sin(C) = (AD ÷ AC)

Since AD = AC , Hence Sin (B) = Sin (C) = 1

Also From definition of similar triangles ABD and ACD are Similar (i.e their corresponding angles are congruent and the corresponding sides are in proportion)

Answer:

1 is h/c

2 is c sin(b)=h

3 is h/b

4 is b sin(c)=h

5 is substitution

6 is bc

Step-by-step explanation:

right on edge 2020