Question:
Triangle ABC is a right triangle
The length of BC is 5 units.
The area of ABC is ______ square units.
Cordinates are given below.
A(-9, 10)
B(7, -2)
C(4,-6)
Answer:
50 square units
Step-by-step explanation:
Image to question is attached.
Given:
Length of BC = 5 units
Coordinates:
A = (-9, 10)
B= (7, -2)
C = (4, -6)
Let's take BC as base, and AB as height.
Since we know length of BC, let's find length of AB.
Length of AB =
[tex] \sqrt{(-9 - 7)^2 +(10 + 2)^2 [/tex]
[tex] = \sqrt{(256)+(144) [/tex]
= 20.
Therefore, the area of triangle ABC [tex] = \frac{1}{2} b*h [/tex]
[tex] = \frac {1}{2} * 5 * 20 [/tex]
= 50 square units.
