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Calculator question.

Whats is the minimum window that allows r^2=4cos(2theta)

multiple choice

A. [0,2pi]

B. [0,pi]

C. [-2pi,2pi]

D [0,pi/2]

Respuesta :

anicalculus

Answer:

D. [0,pi/2]

Step-by-step explanation:

when Ф = 0 in radian

r²=  4cos (2(0))

r² = 4 * 1

r² = 4

∴ r = √4 = 2

r = 2.

when Ф = π/2 in radian

r²=  4cos (2(π/2))

r² = 4 * -1

r² = -4

∴ r = 0

tylermetzger

Answer:

doing this so anicalculus can get brainliest

Step-by-step explanation:

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