Answer:
The percentage deviation is [tex]\Delta M = 1.87[/tex]%
Explanation:
From the question we are told that
The concentration is of the solution is [tex]C = 1.0*10^{-5} M[/tex]
The true absorbance A = 0.7526
The percentage of transmittance due to stray light [tex]z = 0.56[/tex]% [tex]=\frac{0.56}{100} = 0.0056[/tex]
Generally Absorbance is mathematically represented as
[tex]A = -log T[/tex]
Where T is the percentage of true transmittance
Substituting value
[tex]0.7526 = - log T[/tex]
[tex]T = 10^{-0.7526}[/tex]
[tex]= 0.177[/tex]
[tex]= 17.7[/tex]%
The Apparent absorbance is mathematically represented
[tex]A_p = -log (T +z)[/tex]
Substituting values
[tex]A_p = -log(0.177 + 0.0056)[/tex]
[tex]= -log(0.1826)[/tex]
= 0.7385
The percentage by which apparent absorbance deviates from known absorbance is mathematically evaluated as
[tex]\Delta A = \frac{A -A_p}{A} * \frac{100}{1}[/tex]
[tex]= \frac{0.7526 - 0.7385}{0.7526} * \frac{100}{1}[/tex]
[tex]\Delta A = 1.87[/tex]%
Since Absorbance varies directly with concentration the percentage deviation of the apparent concentration from know concentration is
[tex]\Delta M = 1.87[/tex]%
