Answer:
407 KJ
Explanation:
Q = m x Hv / M(H2O)
Q = 180 x 40,67/ 18
Q = 407 kJ
-406.7 kJ is the change in enthalpy when 180 g of water vapor condenses at 100°C.
Enthalpy is the sum of the internal energy. and pressure times volume. We cannot measure the enthalpy of a system, but we can look at changes in enthalpy.
[tex]H_2O (l)[/tex] → [tex]H_2O (g)[/tex], Δ[tex]H_V[/tex] = - 40.67kJ/mol
Mole of water =[tex]\frac{180g}{18g/mol}[/tex]
Mole of water = 10g
Heat of condensation of 1 mol of water = Δ[tex]H_V[/tex]
= - 40.67kJ/mol
Heat change when 180 g of water condenses at 100° C:
= - 40.67kJ/mol X 10g
= - 406.7 kJ
Hence, -406.7 kJ is the change in enthalpy when 180 g of water vapor condenses at 100°C.
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