An artist creates a cone shaped sculpture for an art exhibit. If the sculpture is 6 feet tall and has a base with a circumference of 20.724 feet, what is the volume of the sculpture?

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Answer:

The correct answer is 68.33 cubic feet.

Step-by-step explanation:

An artist creates a cone shaped sculpture for an art exhibit.

Height of the sculpture is 6 feet.

Circumference of the base is 20.724 feet.

Base of a cone is in the shape of a circle with circumference 20.724 feet.

Therefore 2 × π × r = 20.724, where r is the radius of the base and π = [tex]\frac{22}{7}[/tex].

⇒ r = 3.297

Volume of the sculpture = [tex]\frac{1}{3}[/tex] × π × h × [tex]r^{2}[/tex] =  [tex]\frac{1}{3}[/tex] × π × 6 × [tex]3.297^{2}[/tex] = 68.327028 ≈ 68.33 cubic feet.