0.216 g of water is formed.
According to the question,
The concentration of HCl and NaOH are:
→ [tex]CHCl = \frac{20\times 0.80}{50}[/tex]
[tex]= 0.32 \ M[/tex]
→ [tex]CNaOH = \frac{30\times 0.40}{50}[/tex]
[tex]= 0.24 \ M[/tex]
Upon the reaction,
It will form 0.24 M of NaCl as well as 0.24 M of H₂O in 50 mL solution.
In 1000 mL,
→ [tex]1 M \ H_2O = 18 \g \ H_2O[/tex]
Now,
→ 50 mL of 0.24 M H₂O will contain:
= [tex](18\times 0.24)\times \frac{50}{1000}[/tex]
= [tex]0.216 \ g[/tex] (water)
Thus the response above is right.
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