Answer:
For each 1.5 cm the input piston moves, then output piston will move 0.5 cm
Explanation:
Let cross-sectional area of the input piston = A
Let cross-sectional area of the output piston = 3A
pressure (P) = Force (F) / Area (A)
F = PA
For a constant gravitational force on the inlet and outlet piston;
P₁A₁ = P₂A₂
But pressure = ρgh
where;
ρ is density of water
g is acceleration due to gravity
h is the distance or height moved by the piston
(ρg)h₁A₁ = (ρg)h₂A₂
h₁A₁ = h₂A₂
Area of output piston = 3 times area of input piston
h₁A₁ = h₂(3A₁)
For each 1.5 cm the input piston moves, then output piston will move;
1.5A₁ = h₂(3A₁)
1.5 = 3h₂
h₂ = 1.5 / 3
h₂ = 0.5 cm
Thus, for each 1.5 cm the input piston moves, then output piston will move 0.5 cm
