Respuesta :

Answer:49.3

Explanation:4.1j/g c * 25g * (t2-45c)=455j

T2-45c = 455j/4.1j/g c * 25g

455/104.6

45+4.3= 49.3 celsius

samueladesida43

The final temperature of water if 455 J of heat is transferred to 25.0g of water at 45.0 degrees Celsius is 63.2°C.

How to calculate final temperature?

The final temperature of water can be calculated using the following formula:

Q = m × c × ∆T

Where;

  • Q = quantity of heat absorbed or released
  • m = mass of substance
  • c = specific heat capacity
  • ∆T = change in temperature

According to this question, 455 J of heat is transferred to 25.0g of water at 45.0 degrees Celsius.

455 = 25 × (T - 45)

455 = 25T - 1125

25T = 1580

T = 63.2°C

Therefore, the final temperature of water if 455 J of heat is transferred to 25.0g of water at 45.0 degrees Celsius is 63.2°C.

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