Answer:
6 m²
Explanation:
application of fluid pressure according to Pascal's principle for the two pistons is given as:
[tex]P_1=P_2[/tex]
Where P₁ is the pressure at the input and P₂ is the pressure at the output.
But P₁ = F₁ / A₁ and P₂ = F₂ / A₂
Where F₁ and F₂ are the forces applied at the input and output respectively and A₁ and A₂ are the area of the input pipe and output pipe respectively
Since, [tex]P_1=P_2[/tex]
[tex]\frac{F_1}{A_1} =\frac{F_2}{A_2}\\[/tex]
But A₁ = 0.2 m², F₁ = 250 N, F₂ = 7500 N. Substituting values to get:
[tex]\frac{F_1}{A_1} =\frac{F_2}{A_2}\\\frac{250}{0.2}=\frac{7500}{A_2}\\ A_2=\frac{7500*0.2}{250} = 6m^2[/tex]
Therefore, the area of the pipe below the load is 6 m²
