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an airplane flies from point A to point B Point A is 40 kilometers from a ground signal at point C point B is 56 kilometers from the same ground signal if AB=80 find the measure of ACB to the nearest degree



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lucic

Answer:

ACB = 112°

Step-by-step explanation:

First form a sketch where will have a triangle sketch showing the points ABC with AB= 80km and CB = 56 km

Apply the law of cosine as;

c²=a²+b²-2ab*cos(C)

To get angle C;

C=arccos((a²+b²-c²)/(2ab))

Substitute values given in the equation as

C=arccos((40²+56²-80²)/(2*40*56))

C=arccos(-1664/4480)

C=112°

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