contestada

Rank the species (amide ion, ammonia, or ammonium ion) from the largest to the smallest H−N−HH−N−H bond angle? Rank from largest to smallest H−N−HH−N−H bond angle. To rank items as equivalent, overlap them.

Respuesta :

emaikwuvictor

Answer:

H-N-H bond in Amide> H-N-H bond in Ammonium > H-N-H bond in ammonia

Explanation:

Amide has a planar shape with 120° H-N-H bond, ammonium has a tetrahedral shaped H-N-H bond of 109°, while ammonia has a pyramidal geometry of H-N-H bond angle of 107°

pstnonsonjoku

The bond angles of the species in decreasing order is ammonium ion > ammonia > amide ion.

The bond angle refers to the angle between two atoms bonded to the same central atom. The bond angle depends on the type of electron pairs that surround the valence shell of the central atom. Recall that lone pairs cause more repulsion than bond pairs hence they take up more space around the central atom and tend to squeeze the bond angles.

Having said this, we must recall that the amide ion has two lone pairs on the nitrogen central atom. Ammonia has one lone pair on the nitrogen central atom while ammonium ion has no lone pair. The shape of all three species is based on a tetrahedron. The bond angles of the species in decreasing order is ammonium ion > ammonia > amide ion.

Learn more: https://brainly.com/question/14191541

Otras preguntas