Answer:
Vertical velocity [tex]V_y = 10.89 \ m/s[/tex]
Horizontal velocity [tex]V_x = 15.57 \ m/s[/tex]
Explanation:
If a 1 -kg is thrown vertically with a velocity of 19 m/s at an angle of 35 °C from a height 1.94 m
The vertical and horizontal component can be resolved as:
[tex]V_y = Vsin \theta \\ \\ \\\\V_x = Vcos \theta[/tex]
For Vertical component :
[tex]V_y = V sin \theta \\\\V_y = 19 * sin 35 \\ \\ V_y = 19* 0..5736 \\ \\ V_y = 10.89 \ m/s[/tex]
For horizontal velocity
[tex]V_x = V cos \theta \\\\V_x = 19 * cos 35 \\ \\ V_x = 19* 0.8192 \\ \\ V_x = 15.57 \ m/s[/tex]
