Answer:
[-16,-4]
Step-by-step explanation:
We are given that
[tex]f(x)=2x^2+6x-12[/tex]
Domain=[-2,1]
We have to find the set of range values of f(x).
Substitute x=-2
[tex]f(-2)=2(-2)^2+6(-2)-12[/tex]
[tex]f(-2)=-16[/tex]
Substitute x=1
[tex]f(1)=2(1)+6(1)-12=-4[/tex]
Range of f(x)=[-16,-4]
Hence, the set of range values of f(x)
[-16,-4]