Answer:
0
Explanation:
we have ,
T = 298K temperature
P = 1.00 bar. pressure
M = 123g. mass CO
a) Adiabatic reversible expansion
q= 0. Heat is zero
we know the total entropy change is
ΔS total = Δs + Δs surrounding
ΔS surrounding = -q/ T
So, ΔS surrounding= 0
in reversible process,
ΔS= 0
Change in entropy should be positive for spontaneous process ΔS total ≥0
Therefore,
ΔS total= ΔS + ΔS surrounding
= 0
Hence, we can say that the process is not spontaneous, so the system and surrounding are in equilibrium.
