Answer:
[tex](x+6)^2+(y+1)^2=38[/tex]
Step-by-step explanation:
We are given that
[tex]x^2+y^2+12x+2y-1=0[/tex]
The equation can be written as
[tex]x^2+2\times 6x+(6)^2-36+y^2+2\times y+1-1-1=0[/tex]
[tex](x^2+2\times x \times 6+36)+(y^2+2\times y\times 1+1)-36-1-1=0[/tex]
We know that
[tex]a^2+b^2+2ab=(a+b)^2[/tex]
Using the formula
[tex](x+6)^2+(y+1)^2-36-1-1=0[/tex]
[tex](x+6)^2+(y+1)^2-38=0[/tex]
[tex](x+6)^2+(y+1)^2=38[/tex]
