Respuesta :
Answer:
37.8metres
Step-by-step explanation:
The arc of the arrow can be modeled by the equation:
y=-0.02x²+0.65x+4
Where x is the horizontal distance (in meters) from Linda and y is the height (in meters) of the arrow.
The arrow hits the ground when its height (y) is zero.
Therefore, we determine the value(s) of x for which:
y=-0.02x²+0.65x+4=0
Using a calculator to solve the quadratic equation:
x=37.79 or -5.29
Since the distance cannot be a negative value, we ignore -5.29.
The distance from Linda when the arrow hits the ground is 37.8metres (to the nearest tenth)
Answer:
37.8 m
Step-by-step explanation:
Given:-
- The arc trajectory of the arrow is modeled by:
y = -0.02x^2 + 0.65x + 4
Where, x is the horizontal distance (in meters) from Linda
y is the height (in meters) of the arrow
Find:-
How far from Linda does the arrow hit the ground? Round to the nearest tenth.
Solution:-
- We are to determine the range of the projectile trajectory of the arrow. The maximum distance "x_max" occurs when the arrow hits the ground.
- Set the trajectory height of arrow from linda , y = 0:
0 = -0.02x^2 + 0.65x + 4
- Solve the quadratic equation:
x = -5.29 m , x = 37.8 m
- The negative distance x lies at the back of Linda and hence can be ignored. The maximum distance travelled by the arrow would be = 37.8 m
