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In ΔCDE, the measure of ∠E=90°, the measure of ∠D=38°, and DE = 12 feet. Find the length of CD to the nearest tenth of a foot.

Respuesta :

Given:

Given that the triangle CDE is a right triangle.

The measure of ∠E is 90° and ∠D is 38°

The length of DE is 12 feet.

We need to determine the length of CD.

Length of CD:

The length of CD can be determined using the trigonometric ratio.

Thus, we have;

[tex]cos \ \theta=\frac{adj}{hyp}[/tex]

where [tex]\theta=D[/tex] and the side adjacent to angle D is ED and hypotenuse is CD.

Substituting these values, we get;

[tex]cos \ D=\frac{ED}{CD}[/tex]

where ∠D = 38°, ED = 12 feet.

Substituting, we get;

[tex]cos \ 38^{\circ}=\frac{12}{CD}[/tex]

Simplifying, we have;

[tex]CD=\frac{12}{cos \ 38^{\circ}}[/tex]

[tex]CD=\frac{12}{0.788}[/tex]

Dividing, we get;

[tex]CD=15.2[/tex]

Thus, the length of CD is 15.2 feet.

Ver imagen vijayalalitha

Answer:

51.6

Step-by-step explanation:

its because you have to use cos toh and all of the calculator functions