Solve for an angle in right triangles help

Answer:
64.62 degrees
Step-by-step explanation:
Cosine adjacent/hypotenuse (sides)
CosB = (3/7)
B = [tex]Cos^{-1}[/tex](3/7)
B = 64.62
Answer:
64.62
Step-by-step explanation:
AC²= AB²-BC²
[tex]AC = \sqrt{ {(7)}^{2} - ({3)}^{2} } [/tex]
[tex] = \sqrt{49 - 9} = \sqrt{40} = 2 \sqrt{10} [/tex]
[tex] \tan(B) = \frac{AC }{ BC} [/tex]
[tex] B = { \tan}^{ - 1} \frac{2 \sqrt{10} }{3} [/tex]
[tex] = 64.62[/tex]