A square's diagonal (hypotenuse) is 28V2. What is the length of each side?

In a square, all four sides are the same length. Imagine a square that has been cut by a diagonal. We have two triangles, each with the same length hypotenuse (diagonal length) and two equal side lengths. To find the length of each side, we can use the Pythagorean theorem.
I used x in place of a and b, as both side lengths are equal.
x^2 + x^2 = (28 [tex]\sqrt{2}[/tex])^2
2x^2 = 1568
x^2 = 784
x = 28
The length of each side is 28 units.
Hope this helps!! :)
Answer:
Once it is a square, the lengths are the same. Considering that
a square's diagonal is [tex]s\sqrt{2}[/tex], thus, each length measures 28.
You may use the pythagorean theorem:
[tex](28\sqrt{2} )^2=s^2+s^2\\28\sqrt{2} =\sqrt{s^2+s^2} \\28\sqrt{2} =s\sqrt{2} \\[/tex]