Answer:
(f-g)(x) = -x^2 - 2x +2.
Step-by-step explanation:
(f-g)(x)=f(x) - g(x)= (x-2)-(x^2+3x-4)
= x-2 -x^2 -3x +4
= -x^2 - 2x +2.
Then , the answer is (f-g)(x)= -x^2 - 2x +2.
Hope that you understand.
Value of the given function [tex](f-g)x = -x^{2} -2x+2[/tex].
" Function is defined as when all the input values are related to one output each."
According to the question,
Given functions,
[tex]f(x) = x-2\\\\g(x) = x^{2} +3x-4[/tex]
Substitute the value of given function in (f-g)x we get,
[tex](f-g)x = f(x) -g(x)[/tex]
[tex]= (x-2)-(x^{2} +3x-4)\\= x-2-x^{2} -3x+4\\= -x^{2} -2x+2[/tex]
Hence, value of the given function [tex](f-g)x = -x^{2} -2x+2[/tex].
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