Answer:
3/10 or 30% chance red and green being pulled
Step-by-step explanation:
to get your fraction you do your amount wanted pulled (red and green) over the amount total (all of the colors)
24 + 12 = 36
40 + 24 + 12 + 24 + 20 = 120
36/120 now reduce 6
6/20 reduce by 2
3/10
To solve this problem, we have to use probability on this and calculate the probability of choosing a green or red candy.
The probability of selecting a red or green candy from the box is 0.3
This is the branch of mathematics that deals with numerical calculations of the chance of an event is to occur.
Data;
Let's calculate the total number of candies in this data set
[tex]40+24+24+12+20= 120[/tex]
The total number of candies present in the box is 120.
The probability of choosing a green or red candy is
[tex]\frac{24+12}{120}=\frac{36}{120}=\frac{3}{10} =0.3[/tex]
The probability of selecting a red or green candy from the box is 0.3
Learn more on probability here;
https://brainly.com/question/24756209
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