contestada

Write the standard equation of the circle with the given center and passes through the given point. Center (7,-2); Point= (1,-6). Formula: (x-h)^2+(y-k)^2=r^2

Respuesta :

altavistard

Answer:

(x - 7)² + (y + 2)² = (2√13)²

Step-by-step explanation:

We already know that the center is at (7, -2), but must find the radius.  The radius is the distance between the points (7, -2) and (1, -6):

r = √ [6² + 4²] ) = √(36 + 16) = √52 = √4√13 = 2√13.

Then the desired equation is (x - 7)² + (y + 2)² = (2√13)²

Otras preguntas