Answer:
a. 2, 4, 8, 14, 22, 32
b. 5, 7, 11, 17, 25, 35
c. 16, 18, 22, 28, 36, 46
Step-by-step explanation:
a. Add each of the first differences to the previous term.
first term: 2 . . . (given)
second term: 2 +2 = 4
third term: 4 +4 = 8
fourth term: 8 +6 = 14
fifth term: 14 +8 = 22
sixth term: 22 +10 = 32
The first 6 terms of the sequence are 2, 4, 8, 14, 22, 32.
__
b. If the first term is n, then the second term is n+2, and their sum is ...
n +(n+2) = 12
n = (12 -2)/2 = 5 . . . . solve for n
The first 6 terms of the sequence are 5, 7, 11, 17, 25, 35.
__
c. You may have noticed from the above that the 5th term is 20 more than the first term. For this sequence, the first term will be 36 -20 = 16.
The first 6 terms of the sequence are 16, 18, 22, 28, 36, 46.
