Respuesta :
Slope-intercept form: y = mx + b
(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)
To find the slope(m), use the slope formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex] And plug in the two points on the line
(1, 4) = (x₁, y₁)
(3, -4) = (x₂, y₂)
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]m=\frac{-4-4}{3-1}[/tex]
[tex]m=\frac{-8}{2}[/tex] Simplify the fraction
m = -4
Now that you know the slope, substitute/plug it into the equation.
y = mx + b
y = -4x + b To find b, plug in either of the points into the equation, it doesn't matter which, the isolate/get the variable "b" by itself. I will use (1, 4)
4 = -4(1) + b Add 4 on both sides to get "b" by itself
4 + 4 = -4 + 4 + b
8 = b
y = -4x + 8 Your answer is the 1st option
