Respuesta :

Answer:

C (3rd option)

You divide the fraction into 2 separate fraction, one with ONLY the x values and one with ONLY the y values. Divide the x^2 by the x^4, and get 1/(x^2). You divide the y^3 by y^2, and get y. You multiply these 2 together, and get y/(x^2). This is C

When a base with an exponent is divided by a base with an exponent, you subtract the exponents together. (But you can only combine the exponents when the bases are the same)

For example:

[tex]\frac{x^2}{y^3}[/tex]   (Can't combine the exponents as they have different bases of x and y)

[tex]\frac{x^5}{x^3} =x^{(5-3)}=x^2[/tex]

[tex]\frac{y^8}{y^1} = y^{(8-1)}=y^7[/tex]

When you have a negative exponent, you move the base with the negative exponent to the other side of the fraction to make the exponent positive.

For example:

[tex]x^{-3}[/tex] or  [tex]\frac{x^{-3}}{1}=\frac{1}{x^3}[/tex]

[tex]\frac{1}{y^{-2}} =\frac{y^2}{1}[/tex] or [tex]y^2[/tex]

[tex]\frac{x^2y^3}{x^4y^2} =x^{(2-4)}y^{(3-2)}=x^{-2}y^1=\frac{y}{x^2}[/tex]  

Your answer is the 3rd option: Mrs. Gamma.....